In the given figure, O is the centre of a circle and ∠ ACB=30∘. Then, ∠ AOB = ? a 30∘ b 15∘ c 60∘ d 90∘
In the given figure- O is the centre of a circle and - ACB-30- Then- - AOB - - a 30- b 15- c 60- d 90
In the above diagram, O is centre of the circle and ( angle O P A = 30 ^ { circ } ) Find ( angle A C B ) and ( angle A D B ) respectively ( 0120 ^ { circ } , 60 ^ { circ } ) ( 60 ^ { circ } , 120 ^ { circ } ) ( 075 ^ { circ } , 105 ^ { circ } ) ( 35
In the figure, O is the centre of circle, angle ABO=20^{o} and angle ACO=30^{o}, where A,B,C are points on the circle. The value of x is :120^{o}130^{o}100^{o}150^{o}
15. In the following figure, O is the centre of thencircle,n
Solved] In the following figure, O is the centre of the circle and D
In the adjoining figure,O is centre of the circle , If ` angle ACB= 30^(@),
In Fig. 10.36, A, B and C are three points on a circle with center O
In the figure, O is the center and angle ACB=20^°. Then the angle
In Figure, A,B and C are three points on a circle with centre O
In Fig. 9.4, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the tangent to the circle at the point A
In the following figure, if O is the center of the circle and bar
In the figure, O is the center of the circle. If ∠ ACB =30∘ then ∠ ABC equal to :A. 15∘B. 60∘C. 45∘D. 30∘
